How to solve 7x+7-3x+3=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7x+7-3x+3=0 | Equatix

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$$7x+7-3x+3=0$$

$x = -\frac{5}{2} = -2\frac{1}{2} = -2.5$

Combine $7x$ and $-3x$ to get $4x$.

$$4x+7+3=0$$

Add $7$ and $3$ to get $10$.

$$4x+10=0$$

Subtract $10$ from both sides. Anything subtracted from zero gives its negation.

$$4x=-10$$

Divide both sides by $4$.

$$x=\frac{-10}{4}$$

Reduce the fraction $\frac{-10}{4}$ to lowest terms by extracting and canceling out $2$.

$$x=-\frac{5}{2}$$