$$7y+10x=-11; 4y-3x=-15; x=; y=$$
$z=1$
$$z=x$$ $$4y-3x=-15$$ $$7y+10x=-11$$
$$x=z$$
$$4y-3z=-15$$ $$7y+10z=-11$$
$$y=-\frac{15}{4}+\frac{3}{4}z$$ $$z=-\frac{7}{10}y-\frac{11}{10}$$
$$z=-\frac{7}{10}\left(-\frac{15}{4}+\frac{3}{4}z\right)-\frac{11}{10}$$
$$z=1$$
$$y=-\frac{15}{4}+\frac{3}{4}\times 1$$
$$y=-3$$
$$x=1$$
$$y=-3$$ $$x=1$$ $$z=1$$
Show Solution
Hide Solution