How to solve 7z + 13 = 2z + 4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7z + 13 = 2z + 4 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7z+13=2z+4$$

Solve for z

$z = -\frac{9}{5} = -1\frac{4}{5} = -1.8$

Steps for Solving Linear Equation

Subtract $2z$ from both sides.

$$7z+13-2z=4$$

Combine $7z$ and $-2z$ to get $5z$.

$$5z+13=4$$

Subtract $13$ from both sides.

$$5z=4-13$$

Subtract $13$ from $4$ to get $-9$.

$$5z=-9$$

Divide both sides by $5$.

$$z=\frac{-9}{5}$$

Fraction $\frac{-9}{5}$ can be rewritten as $-\frac{9}{5}$ by extracting the negative sign.

$$z=-\frac{9}{5}$$

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Question

Solve for z

Steps for Solving Linear Equation