$$8 { \left(x-1 \right) }^{ 3 } -27 { \left(x+2 \right) }^{ 3 }$$
$-\left(x+8\right)\left(19x^{2}+34x+28\right)$
$$8\left(x^{3}-3x^{2}+3x-1\right)-27\left(x+2\right)^{3}$$
$$8x^{3}-24x^{2}+24x-8-27\left(x+2\right)^{3}$$
$$8x^{3}-24x^{2}+24x-8-27\left(x^{3}+6x^{2}+12x+8\right)$$
$$8x^{3}-24x^{2}+24x-8-27x^{3}-162x^{2}-324x-216$$
$$-19x^{3}-24x^{2}+24x-8-162x^{2}-324x-216$$
$$-19x^{3}-186x^{2}+24x-8-324x-216$$
$$-19x^{3}-186x^{2}-300x-8-216$$
$$-19x^{3}-186x^{2}-300x-224$$
Show Solution
Hide Solution
$-19x^{3}-186x^{2}-300x-224$
