Solve 8(x)^(3)-5(x)^(2)-6x+4\divx+2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8 { x }^{ 3 } -5 { x }^{ 2 } -6x+4 \div x+2$$

Evaluate

$8x^{3}-5x^{2}-6x+2+\frac{4}{x}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $8x^{3}-5x^{2}-6x+2$ times $\frac{x}{x}$.

$$\frac{\left(8x^{3}-5x^{2}-6x+2\right)x}{x}+\frac{4}{x}$$

Since $\frac{\left(8x^{3}-5x^{2}-6x+2\right)x}{x}$ and $\frac{4}{x}$ have the same denominator, add them by adding their numerators.

$$\frac{\left(8x^{3}-5x^{2}-6x+2\right)x+4}{x}$$

Do the multiplications in $\left(8x^{3}-5x^{2}-6x+2\right)x+4$.

$$\frac{8x^{4}-5x^{3}-6x^{2}+2x+4}{x}$$

Factor

$\frac{8x^{4}-5x^{3}-6x^{2}+2x+4}{x}$