Question

$$8 { X }^{ 4- } 18 { x }^{ 3 } -75 { x }^{ 2 } +46x+120$$

Answer

$$144*X^(4-)*x^3-75*x^2+46*x+120$$

Solution


Simplify  \(8{X}^{4-}\times 18{x}^{3}\)  to  \(144{X}^{4-}{x}^{3}\).
\[144{X}^{4-}{x}^{3}-75{x}^{2}+46x+120\]