$$8/(3-5)-2 \times [-3 \times (1-4)-6/(1-3)]$$
$-28$
$$\frac{8}{-2}-2\left(-3\left(1-4\right)-\frac{6}{1-3}\right)$$
$$-4-2\left(-3\left(1-4\right)-\frac{6}{1-3}\right)$$
$$-4-2\left(-3\left(-3\right)-\frac{6}{1-3}\right)$$
$$-4-2\left(9-\frac{6}{1-3}\right)$$
$$-4-2\left(9-\frac{6}{-2}\right)$$
$$-4-2\left(9-\left(-3\right)\right)$$
$$-4-2\left(9+3\right)$$
$$-4-2\times 12$$
$$-4-24$$
$$-28$$
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