How to solve 8 = 4 + 3/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8 = 4 + 3/2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8=4+3\div2$$

Verify

$\text{false}$

Solution Steps

Convert $4$ to fraction $\frac{8}{2}$.

$$8=\frac{8}{2}+\frac{3}{2}$$

Since $\frac{8}{2}$ and $\frac{3}{2}$ have the same denominator, add them by adding their numerators.

$$8=\frac{8+3}{2}$$

Add $8$ and $3$ to get $11$.

$$8=\frac{11}{2}$$

Convert $8$ to fraction $\frac{16}{2}$.

$$\frac{16}{2}=\frac{11}{2}$$

Compare $\frac{16}{2}$ and $\frac{11}{2}$.

$$\text{false}$$

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