How to solve 8-2x=-4,x=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8-2x=-4,x= | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8-2x=-4,x=$$

Solve for x, y

$y=6$

Solution Steps

Consider the first equation. Subtract $8$ from both sides.

$$-2x=-4-8$$

Subtract $8$ from $-4$ to get $-12$.

$$-2x=-12$$

Divide both sides by $-2$.

$$x=\frac{-12}{-2}$$

Divide $-12$ by $-2$ to get $6$.

$$x=6$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=6$$

The system is now solved.

$$x=6$$ $$y=6$$

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Question

Solve for x, y

Solution Steps