How to solve 8-[5-{3-(2-1)}]-2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8-[5-{3-(2-1)}]-2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8-[5- \{ 3-(2-1) \} ]-2$$

Evaluate

$3$

Solution Steps

Subtract $1$ from $2$ to get $1$.

$$8-\left(5-\left(3-1\right)\right)-2$$

Subtract $1$ from $3$ to get $2$.

$$8-\left(5-2\right)-2$$

Subtract $2$ from $5$ to get $3$.

$$8-3-2$$

Subtract $3$ from $8$ to get $5$.

$$5-2$$

Subtract $2$ from $5$ to get $3$.

$$3$$

Show Solution

Factor

$3$

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