$$8 p ^ { 3 } + \frac { 12 } { 5 } p ^ { 2 } + \frac { 6 } { 25 } p + \frac { 1 } { 125 }$$
$\frac{\left(10p+1\right)^{3}}{125}$
$$\frac{1000p^{3}+300p^{2}+30p+1}{125}$$
$$\left(10p+1\right)^{3}$$
$$\frac{\left(10p+1\right)^{3}}{125}$$
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