How to solve 8(2)-z(3)+2(z)=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8(2)-z(3)+2(z)=0 | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8(2)-z(3)+2(z)=0$$

Solve for z

$z=16$

Steps for Solving Linear Equation

Multiply $8$ and $2$ to get $16$.

$$16-z\times 3+2z=0$$

Multiply $-1$ and $3$ to get $-3$.

$$16-3z+2z=0$$

Combine $-3z$ and $2z$ to get $-z$.

$$16-z=0$$

Subtract $16$ from both sides. Anything subtracted from zero gives its negation.

$$-z=-16$$

Multiply both sides by $-1$.

$$z=16$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for z

Steps for Solving Linear Equation