How to solve 8(3/5)-5(7/10)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8(3/5)-5(7/10) | Equatix

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Question

$$8(3/5)-5(7/10)$$

Evaluate

$\frac{13}{10}=1.3$

Solution Steps

Express $8\times \frac{3}{5}$ as a single fraction.

$$\frac{8\times 3}{5}-5\times \frac{7}{10}$$

Multiply $8$ and $3$ to get $24$.

$$\frac{24}{5}-5\times \frac{7}{10}$$

Express $5\times \frac{7}{10}$ as a single fraction.

$$\frac{24}{5}-\frac{5\times 7}{10}$$

Multiply $5$ and $7$ to get $35$.

$$\frac{24}{5}-\frac{35}{10}$$

Reduce the fraction $\frac{35}{10}$ to lowest terms by extracting and canceling out $5$.

$$\frac{24}{5}-\frac{7}{2}$$

Least common multiple of $5$ and $2$ is $10$. Convert $\frac{24}{5}$ and $\frac{7}{2}$ to fractions with denominator $10$.

$$\frac{48}{10}-\frac{35}{10}$$

Since $\frac{48}{10}$ and $\frac{35}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-35}{10}$$

Subtract $35$ from $48$ to get $13$.

$$\frac{13}{10}$$

Show Solution

Factor

$\frac{13}{2 \cdot 5} = 1\frac{3}{10} = 1.3$