$$8(a-3)-2(3-a)=2(a+2)-5(5-a)$$
$a=3$
$$8a-24-2\left(3-a\right)=2\left(a+2\right)-5\left(5-a\right)$$
$$8a-24-6+2a=2\left(a+2\right)-5\left(5-a\right)$$
$$8a-30+2a=2\left(a+2\right)-5\left(5-a\right)$$
$$10a-30=2\left(a+2\right)-5\left(5-a\right)$$
$$10a-30=2a+4-5\left(5-a\right)$$
$$10a-30=2a+4-25+5a$$
$$10a-30=2a-21+5a$$
$$10a-30=7a-21$$
$$10a-30-7a=-21$$
$$3a-30=-21$$
$$3a=-21+30$$
$$3a=9$$
$$a=\frac{9}{3}$$
$$a=3$$
Show Solution
Hide Solution
