How to solve 8(a + 2) > - 16

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8(a + 2) > - 16 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8(a+2)>-16$$

Solve for a

$a>-4$

Solution Steps

Divide both sides by $8$. Since $8$ is positive, the inequality direction remains the same.

$$a+2>\frac{-16}{8}$$

Divide $-16$ by $8$ to get $-2$.

$$a+2>-2$$

Subtract $2$ from both sides.

$$a>-2-2$$

Subtract $2$ from $-2$ to get $-4$.

$$a>-4$$

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Solve for a

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