How to solve 8(x-1) > 3(1-3x)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8(x-1) > 3(1-3x) | Equatix

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Question

$$8(x-1) > 3(1-3x)$$

Solve for x

$x>\frac{11}{17}$

Solution Steps

Use the distributive property to multiply $8$ by $x-1$.

$$8x-8>3\left(1-3x\right)$$

Use the distributive property to multiply $3$ by $1-3x$.

$$8x-8>3-9x$$

Add $9x$ to both sides.

$$8x-8+9x>3$$

Combine $8x$ and $9x$ to get $17x$.

$$17x-8>3$$

Add $8$ to both sides.

$$17x>3+8$$

Add $3$ and $8$ to get $11$.

$$17x>11$$

Divide both sides by $17$. Since $17$ is positive, the inequality direction remains the same.

$$x>\frac{11}{17}$$

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