How to solve 8+2x=2(x+4)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8+2x=2(x+4) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8+2x=2(x+4)$$

Solve for x (complex solution)

$x\in \mathrm{C}$

Solution Steps

Use the distributive property to multiply $2$ by $x+4$.

$$8+2x=2x+8$$

Subtract $2x$ from both sides.

$$8+2x-2x=8$$

Combine $2x$ and $-2x$ to get $0$.

$$8=8$$

Compare $8$ and $8$.

$$\text{true}$$

This is true for any $x$.

$$x\in \mathrm{C}$$

Show Solution

Solve for x

$x\in \mathrm{R}$

Solution Steps

Use the distributive property to multiply $2$ by $x+4$.

$$8+2x=2x+8$$

Subtract $2x$ from both sides.

$$8+2x-2x=8$$

Combine $2x$ and $-2x$ to get $0$.

$$8=8$$

Compare $8$ and $8$.

$$\text{true}$$

This is true for any $x$.

$$x\in \mathrm{R}$$

Show Solution

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Example

Question

Solve for x (complex solution)

Solution Steps

Solve for x

Solution Steps