Question

$$8+ \frac{ \sqrt{ 3 \sqrt{ 6 \sqrt{ 9 } } } }{ 8/ }$$

Answer

$$8+(3*2^(1/4))/8$$

Solution


Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[8+\frac{\sqrt{3\sqrt{6\times 3}}}{\frac{8}{}}\]
Simplify  \(6\times 3\)  to  \(18\).
\[8+\frac{\sqrt{3\sqrt{18}}}{\frac{8}{}}\]
Simplify  \(\sqrt{18}\)  to  \(3\sqrt{2}\).
\[8+\frac{\sqrt{3\times 3\sqrt{2}}}{\frac{8}{}}\]
Simplify  \(3\times 3\sqrt{2}\)  to  \(9\sqrt{2}\).
\[8+\frac{\sqrt{9\sqrt{2}}}{\frac{8}{}}\]
Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[8+\frac{\sqrt{9}\sqrt{\sqrt{2}}}{\frac{8}{}}\]
Since \(3\times 3=9\), the square root of \(9\) is \(3\).
\[8+\frac{3\sqrt{\sqrt{2}}}{\frac{8}{}}\]
Use this rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[8+\frac{3\times {2}^{\frac{1\times 1}{2\times 2}}}{\frac{8}{}}\]
Simplify  \(1\times 1\)  to  \(1\).
\[8+\frac{3\sqrt[2\times 2]{2}}{\frac{8}{}}\]
Simplify  \(2\times 2\)  to  \(4\).
\[8+\frac{3\sqrt[4]{2}}{\frac{8}{}}\]
Invert and multiply.
\[8+3\sqrt[4]{2}\times \frac{1}{8}\]
Simplify  \(3\sqrt[4]{2}\times \frac{1}{8}\)  to  \(\frac{3\sqrt[4]{2}}{8}\).
\[8+\frac{3\sqrt[4]{2}}{8}\]

Decimal Form: 8.445953