How to solve 8 ^ - 2 * 2 ^ 5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8 ^ - 2 * 2 ^ 5 | Equatix

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Question

$$8^{-2}\times2^{5}$$

Evaluate

$\frac{1}{2}=0.5$

Solution Steps

Calculate $8$ to the power of $-2$ and get $\frac{1}{64}$.

$$\frac{1}{64}\times 2^{5}$$

Calculate $2$ to the power of $5$ and get $32$.

$$\frac{1}{64}\times 32$$

Multiply $\frac{1}{64}$ and $32$ to get $\frac{1}{2}$.

$$\frac{1}{2}$$

Show Solution

Factor

$\frac{1}{2} = 0.5$

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