How to solve 1 8x - 3 = 4x + 1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1 8x - 3 = 4x + 1 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8 x - 3 = 4 x + 1$$

Solve for x

$x=1$

Steps for Solving Linear Equation

Subtract $4x$ from both sides.

$$8x-3-4x=1$$

Combine $8x$ and $-4x$ to get $4x$.

$$4x-3=1$$

Add $3$ to both sides.

$$4x=1+3$$

Add $1$ and $3$ to get $4$.

$$4x=4$$

Divide both sides by $4$.

$$x=\frac{4}{4}$$

Divide $4$ by $4$ to get $1$.

$$x=1$$

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Question

Solve for x

Steps for Solving Linear Equation