$$80\div(2\times2+2)+3^{2}-4-2$$
$\frac{49}{3}\approx 16.333333333$
$$\frac{80}{4+2}+3^{2}-4-2$$
$$\frac{80}{6}+3^{2}-4-2$$
$$\frac{40}{3}+3^{2}-4-2$$
$$\frac{40}{3}+9-4-2$$
$$\frac{40}{3}+\frac{27}{3}-4-2$$
$$\frac{40+27}{3}-4-2$$
$$\frac{67}{3}-4-2$$
$$\frac{67}{3}-\frac{12}{3}-2$$
$$\frac{67-12}{3}-2$$
$$\frac{55}{3}-2$$
$$\frac{55}{3}-\frac{6}{3}$$
$$\frac{55-6}{3}$$
$$\frac{49}{3}$$
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$\frac{7 ^ {2}}{3} = 16\frac{1}{3} = 16.333333333333332$
