How to solve 809 imes350

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 809\times350 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$809 \times 350$$

Evaluate

$283150$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}809\\\underline{\times\phantom{999}350}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 809 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}809\\\underline{\times\phantom{999}350}\\\phantom{\times999999}0\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 809 with 5. Write the result 4045 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}809\\\underline{\times\phantom{999}350}\\\phantom{\times999999}0\\\phantom{\times9}4045\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 809 with 3. Write the result 2427 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}809\\\underline{\times\phantom{999}350}\\\phantom{\times999999}0\\\phantom{\times9}4045\phantom{9}\\\underline{\phantom{\times}2427\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}809\\\underline{\times\phantom{999}350}\\\phantom{\times999999}0\\\phantom{\times9}4045\phantom{9}\\\underline{\phantom{\times}2427\phantom{99}}\\\phantom{\times}283150\end{array}$$

Show Solution

Factor

$2\times 5^{2}\times 7\times 809$