How to solve 81 imes236987

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 81\times236987 | Equatix

Question

$$81 \times 236987$$

Evaluate

$19195947$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999999}81\\\underline{\times\phantom{99}236987}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 81 with 7. Write the result 567 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}81\\\underline{\times\phantom{99}236987}\\\phantom{\times99999}567\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 81 with 8. Write the result 648 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}81\\\underline{\times\phantom{99}236987}\\\phantom{\times99999}567\\\phantom{\times9999}648\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 81 with 9. Write the result 729 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}81\\\underline{\times\phantom{99}236987}\\\phantom{\times99999}567\\\phantom{\times9999}648\phantom{9}\\\phantom{\times999}729\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 81 with 6. Write the result 486 at the end leaving 3 spaces to the right like this.

Now multiply the first number with the $5^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 81 with 3. Write the result 243 at the end leaving 4 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}81\\\underline{\times\phantom{99}236987}\\\phantom{\times99999}567\\\phantom{\times9999}648\phantom{9}\\\phantom{\times999}729\phantom{99}\\\phantom{\times99}486\phantom{999}\\\phantom{\times9}243\phantom{9999}\\\end{array}$$

Now multiply the first number with the $6^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 81 with 2. Write the result 162 at the end leaving 5 spaces to the right like this.

Now add the intermediate results to get final answer.

Show Solution

Factor

$3^{4}\times 19\times 12473$

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Steps For Long Multiplication

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