Question

$$81\times3^{h+1}-9\times3^{h}; 81\times3^{n+2}-3\times3^{n+2}$$

Answer

$$81*3^(h+1)-9*3^h;81*3^(n+2)-3^(n+3)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\begin{aligned}&81\times {3}^{h+1}-9\times {3}^{h}\\&81\times {3}^{n+2}-{3}^{1+n+2}\end{aligned}\]
Simplify  \(1+n+2\)  to  \(n+3\).
\[\begin{aligned}&81\times {3}^{h+1}-9\times {3}^{h}\\&81\times {3}^{n+2}-{3}^{n+3}\end{aligned}\]