How to solve 82+7x < -96+20

Q: How to solve 82+7x < -96+20

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 82+7x < -96+20 | Equatix

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Question

$$82+7x < -96+20$$

Solve for x

$x<-\frac{158}{7}$

Solution Steps

Add $-96$ and $20$ to get $-76$.

$$82+7x<-76$$

Subtract $82$ from both sides.

$$7x<-76-82$$

Subtract $82$ from $-76$ to get $-158$.

$$7x<-158$$

Divide both sides by $7$. Since $7$ is positive, the inequality direction remains the same.

$$x<-\frac{158}{7}$$

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