$$84 \quad 90 \% ( x - 10 ) = 63$$
$x = \frac{3040}{283} = 10\frac{210}{283} \approx 10.74204947$
$$84\frac{9}{10}\left(x-10\right)=63$$
$$84\frac{9}{10}x+84\frac{9}{10}\left(-10\right)=63$$
$$84\frac{9}{10}x=63-84\frac{9}{10}\left(-10\right)$$
$$84\frac{9}{10}x=63+1084\frac{9}{10}$$
$$84\frac{9}{10}x=1084\frac{9}{10}+63$$
$$\frac{84\frac{9}{10}x}{84\frac{9}{10}}=\frac{912}{84\frac{9}{10}}$$
$$x=\frac{912}{84\frac{9}{10}}$$
$$x=\frac{3040}{283}$$
Show Solution
Hide Solution