Solve 5 + \{(27.09/3) * 4 1/2\} | Equatix

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Question

$$8.5+\{(27.09\div3)\times4\frac{1}{2}\}$$

Evaluate

$49.135$

Solution Steps

Expand $\frac{27.09}{3}$ by multiplying both numerator and the denominator by $100$.

$$8.5+\frac{2709}{300}\times \frac{4\times 2+1}{2}$$

Reduce the fraction $\frac{2709}{300}$ to lowest terms by extracting and canceling out $3$.

$$8.5+\frac{903}{100}\times \frac{4\times 2+1}{2}$$

Multiply $4$ and $2$ to get $8$.

$$8.5+\frac{903}{100}\times \frac{8+1}{2}$$

Add $8$ and $1$ to get $9$.

$$8.5+\frac{903}{100}\times \frac{9}{2}$$

Multiply $\frac{903}{100}$ times $\frac{9}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$8.5+\frac{903\times 9}{100\times 2}$$

Do the multiplications in the fraction $\frac{903\times 9}{100\times 2}$.

$$8.5+\frac{8127}{200}$$

Convert decimal number $8.5$ to fraction $\frac{85}{10}$. Reduce the fraction $\frac{85}{10}$ to lowest terms by extracting and canceling out $5$.

$$\frac{17}{2}+\frac{8127}{200}$$

Least common multiple of $2$ and $200$ is $200$. Convert $\frac{17}{2}$ and $\frac{8127}{200}$ to fractions with denominator $200$.

$$\frac{1700}{200}+\frac{8127}{200}$$

Since $\frac{1700}{200}$ and $\frac{8127}{200}$ have the same denominator, add them by adding their numerators.

$$\frac{1700+8127}{200}$$

Add $1700$ and $8127$ to get $9827$.

$$\frac{9827}{200}$$

Show Solution

Factor

$\frac{31 \cdot 317}{2 ^ {3} \cdot 5 ^ {2}} = 49\frac{27}{200} = 49.135$