1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8568/14 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$8568\div14$$

Evaluate

$612$

Steps For Long Division Method

Use the $1^{st}$ digit $8$ from dividend $8568$

$$\begin{array}{l}\phantom{14)}\phantom{1}\\14\overline{)8568}\\\end{array}$$

Since $8$ is less than $14$, use the next digit $5$ from dividend $8568$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{14)}0\phantom{2}\\14\overline{)8568}\\\end{array}$$

Use the $2^{nd}$ digit $5$ from dividend $8568$

$$\begin{array}{l}\phantom{14)}0\phantom{3}\\14\overline{)8568}\\\end{array}$$

Find closest multiple of $14$ to $85$. We see that $6 \times 14 = 84$ is the nearest. Now subtract $84$ from $85$ to get reminder $1$. Add $6$ to quotient.

$$\begin{array}{l}\phantom{14)}06\phantom{4}\\14\overline{)8568}\\\phantom{14)}\underline{\phantom{}84\phantom{99}}\\\phantom{14)9}1\\\end{array}$$

Use the $3^{rd}$ digit $6$ from dividend $8568$

$$\begin{array}{l}\phantom{14)}06\phantom{5}\\14\overline{)8568}\\\phantom{14)}\underline{\phantom{}84\phantom{99}}\\\phantom{14)9}16\\\end{array}$$

Find closest multiple of $14$ to $16$. We see that $1 \times 14 = 14$ is the nearest. Now subtract $14$ from $16$ to get reminder $2$. Add $1$ to quotient.

$$\begin{array}{l}\phantom{14)}061\phantom{6}\\14\overline{)8568}\\\phantom{14)}\underline{\phantom{}84\phantom{99}}\\\phantom{14)9}16\\\phantom{14)}\underline{\phantom{9}14\phantom{9}}\\\phantom{14)99}2\\\end{array}$$

Use the $4^{th}$ digit $8$ from dividend $8568$

$$\begin{array}{l}\phantom{14)}061\phantom{7}\\14\overline{)8568}\\\phantom{14)}\underline{\phantom{}84\phantom{99}}\\\phantom{14)9}16\\\phantom{14)}\underline{\phantom{9}14\phantom{9}}\\\phantom{14)99}28\\\end{array}$$

Find closest multiple of $14$ to $28$. We see that $2 \times 14 = 28$ is the nearest. Now subtract $28$ from $28$ to get reminder $0$. Add $2$ to quotient.

$$\begin{array}{l}\phantom{14)}0612\phantom{8}\\14\overline{)8568}\\\phantom{14)}\underline{\phantom{}84\phantom{99}}\\\phantom{14)9}16\\\phantom{14)}\underline{\phantom{9}14\phantom{9}}\\\phantom{14)99}28\\\phantom{14)}\underline{\phantom{99}28\phantom{}}\\\phantom{14)9999}0\\\end{array}$$

Since $0$ is less than $14$, stop the division. The reminder is $0$. The topmost line $0612$ is the quotient. Remove all zeros at the start of the quotient to get the actual quotient $612$.

$$\text{Quotient: }612$$ $$\text{Reminder: }0$$

Show Solution

Factor

$2^{2}\times 3^{2}\times 17$