How to solve 896 > 182 < 2

Q: How to solve 896 > 182 < 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 896 > 182 < 2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

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$$896 > 182 < 2$$

Verify

$\text{false}$

Solution Steps

Compare $896$ and $182$.

$$\text{true}\text{ and }182<2$$

Compare $182$ and $2$.

$$\text{true}\text{ and }\text{false}$$

The conjunction of $\text{true}$ and $\text{false}$ is $\text{false}$.

$$\text{false}$$

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