How to solve 8t + 5 = 2t - 31

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8t + 5 = 2t - 31 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8t+5=2t-31$$

Solve for t

$t=-6$

Steps for Solving Linear Equation

Subtract $2t$ from both sides.

$$8t+5-2t=-31$$

Combine $8t$ and $-2t$ to get $6t$.

$$6t+5=-31$$

Subtract $5$ from both sides.

$$6t=-31-5$$

Subtract $5$ from $-31$ to get $-36$.

$$6t=-36$$

Divide both sides by $6$.

$$t=\frac{-36}{6}$$

Divide $-36$ by $6$ to get $-6$.

$$t=-6$$

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Question

Solve for t

Steps for Solving Linear Equation