How to solve 8x - 3 = x + 19

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8x - 3 = x + 19 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8x-3=x+19$$

Solve for x

$x = \frac{22}{7} = 3\frac{1}{7} \approx 3.142857143$

Steps for Solving Linear Equation

Subtract $x$ from both sides.

$$8x-3-x=19$$

Combine $8x$ and $-x$ to get $7x$.

$$7x-3=19$$

Add $3$ to both sides.

$$7x=19+3$$

Add $19$ and $3$ to get $22$.

$$7x=22$$

Divide both sides by $7$.

$$x=\frac{22}{7}$$

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Solve for x

Steps for Solving Linear Equation