$$8x-3xy+2xyz+2xy-5x+3xy+xy-3x+4xyz$$
$3xy\left(2z+1\right)$
$$x\left(3y+6yz\right)$$
$$6yz+3y$$
$$3\left(2yz+y\right)$$
$$y\left(2z+1\right)$$
$$3xy\left(2z+1\right)$$
Show Solution
Hide Solution