How to solve 8x + 4 = 3(x - 1)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8x + 4 = 3(x - 1) | Equatix

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3(r+2s)=2t-4

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Question

$$8x+4=3(x-1)$$

Solve for x

$x = -\frac{7}{5} = -1\frac{2}{5} = -1.4$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $x-1$.

$$8x+4=3x-3$$

Subtract $3x$ from both sides.

$$8x+4-3x=-3$$

Combine $8x$ and $-3x$ to get $5x$.

$$5x+4=-3$$

Subtract $4$ from both sides.

$$5x=-3-4$$

Subtract $4$ from $-3$ to get $-7$.

$$5x=-7$$

Divide both sides by $5$.

$$x=\frac{-7}{5}$$

Fraction $\frac{-7}{5}$ can be rewritten as $-\frac{7}{5}$ by extracting the negative sign.

$$x=-\frac{7}{5}$$

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Question

Solve for x

Steps for Solving Linear Equation