Solve 8x + 4 = 3(x - 1) + 7 | Equatix - Math Solver

Fractions & Decimals

Ratios & Proportions

Basic Number Theory

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Sequences & Series

Descriptive Statistics

Normal Distribution

Hypothesis Testing

Regression Analysis

Linear Programming

Sets & Counting

Eigenvalues & Eigenvectors

Linear Transformations

Atomic Structure

Thermochemistry

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$8x+4=3(x-1)+7$$

Solve for x

$x=0$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $x-1$.

$$8x+4=3x-3+7$$

Add $-3$ and $7$ to get $4$.

$$8x+4=3x+4$$

Subtract $3x$ from both sides.

$$8x+4-3x=4$$

Combine $8x$ and $-3x$ to get $5x$.

$$5x+4=4$$

Subtract $4$ from both sides.

$$5x=4-4$$

Subtract $4$ from $4$ to get $0$.

$$5x=0$$

Product of two numbers is equal to $0$ if at least one of them is $0$. Since $5$ is not equal to $0$, $x$ must be equal to $0$.

$$x=0$$