Question

$$8x+4=\frac{1}{3}(\frac{1}{x-1)^{1}+7$$

Answer

x=2

Solution


Simplify  \(1\times x\)  to  \(x\).
\[8x+4=13{(x-1)}^{1}+7\]
Use Rule of One: \({x}^{1}=x\).
\[8x+4=13(x-1)+7\]
Expand.
\[8x+4=13x-13+7\]
Simplify  \(13x-13+7\)  to  \(13x-6\).
\[8x+4=13x-6\]
Subtract \(8x\) from both sides.
\[4=13x-6-8x\]
Simplify  \(13x-6-8x\)  to  \(5x-6\).
\[4=5x-6\]
Add \(6\) to both sides.
\[4+6=5x\]
Simplify  \(4+6\)  to  \(10\).
\[10=5x\]
Divide both sides by \(5\).
\[\frac{10}{5}=x\]
Simplify  \(\frac{10}{5}\)  to  \(2\).
\[2=x\]
Switch sides.
\[x=2\]