How to solve 8x+7y=3,x+4=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8x+7y=3,x+4=0 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$8x+7y=3,x+4=0$$

Solve for x, y

$x=-4$
$y=5$

Solution Steps

Consider the second equation. Subtract $4$ from both sides. Anything subtracted from zero gives its negation.

$$x=-4$$

Consider the first equation. Insert the known values of variables into the equation.

$$8\left(-4\right)+7y=3$$

Multiply $8$ and $-4$ to get $-32$.

$$-32+7y=3$$

Add $32$ to both sides.

$$7y=3+32$$

Add $3$ and $32$ to get $35$.

$$7y=35$$

Divide both sides by $7$.

$$y=\frac{35}{7}$$

Divide $35$ by $7$ to get $5$.

$$y=5$$

The system is now solved.

$$x=-4$$ $$y=5$$

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Question

Solve for x, y

Solution Steps