How to solve 8x ^ 2 - 18

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8x ^ 2 - 18 | Equatix

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Question

$$8x^{2}-18$$

Factor

$2\left(2x-3\right)\left(2x+3\right)$

Solution Steps

Factor out $2$.

$$2\left(4x^{2}-9\right)$$

Consider $4x^{2}-9$. Rewrite $4x^{2}-9$ as $\left(2x\right)^{2}-3^{2}$. The difference of squares can be factored using the rule: $a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$.

$$\left(2x-3\right)\left(2x+3\right)$$

Rewrite the complete factored expression.

$$2\left(2x-3\right)\left(2x+3\right)$$

Show Solution

Evaluate

$8x^{2}-18$