$$9 { x }^{ 2 } +5+4 { x }^{ 2 } -4$$
$13x^{2}+1$
$$13x^{2}+5-4$$
$$13x^{2}+1$$
Show Solution
Hide Solution
$26x$
$$\frac{\mathrm{d}}{\mathrm{d}x}(13x^{2}+5-4)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(13x^{2}+1)$$
$$2\times 13x^{2-1}$$
$$26x^{2-1}$$
$$26x^{1}$$
$$26x$$
