Solve 9 - 3 / (1/3) + 1 = ? | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$9 - 3 \div \frac { 1 } { 3 } + 1 = ?$$

Evaluate

$1$

Solution Steps

Divide $3$ by $\frac{1}{3}$ by multiplying $3$ by the reciprocal of $\frac{1}{3}$.

$$9-3\times 3+1$$

Multiply $3$ and $3$ to get $9$.

$$9-9+1$$

Subtract $9$ from $9$ to get $0$.

$$1$$

Factor

$1$