How to solve 9-37+2-8-2+5-8+4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9-37+2-8-2+5-8+4 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$9-37+2-8-2+5-8+4$$

Evaluate

$-35$

Solution Steps

Subtract $37$ from $9$ to get $-28$.

$$-28+2-8-2+5-8+4$$

Add $-28$ and $2$ to get $-26$.

$$-26-8-2+5-8+4$$

Subtract $8$ from $-26$ to get $-34$.

$$-34-2+5-8+4$$

Subtract $2$ from $-34$ to get $-36$.

$$-36+5-8+4$$

Add $-36$ and $5$ to get $-31$.

$$-31-8+4$$

Subtract $8$ from $-31$ to get $-39$.

$$-39+4$$

Add $-39$ and $4$ to get $-35$.

$$-35$$

Show Solution

Factor

$-35$

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