Solve 9(2-3x)-29=8x-(x-23) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$9(2-3x)-29=8x-(x-23)$$

Solve for x

$x=-1$

Steps for Solving Linear Equation

Use the distributive property to multiply $9$ by $2-3x$.

$$18-27x-29=8x-\left(x-23\right)$$

Subtract $29$ from $18$ to get $-11$.

$$-11-27x=8x-\left(x-23\right)$$

To find the opposite of $x-23$, find the opposite of each term.

$$-11-27x=8x-x-\left(-23\right)$$

The opposite of $-23$ is $23$.

$$-11-27x=8x-x+23$$

Combine $8x$ and $-x$ to get $7x$.

$$-11-27x=7x+23$$

Subtract $7x$ from both sides.

$$-11-27x-7x=23$$

Combine $-27x$ and $-7x$ to get $-34x$.

$$-11-34x=23$$

Add $11$ to both sides.

$$-34x=23+11$$

Add $23$ and $11$ to get $34$.

$$-34x=34$$

Divide both sides by $-34$.

$$x=\frac{34}{-34}$$

Divide $34$ by $-34$ to get $-1$.

$$x=-1$$