$$9(5z-4)+3(6z-1)+12z=10$$
$z=\frac{49}{75}\approx 0.653333333$
$$45z-36+3\left(6z-1\right)+12z=10$$
$$45z-36+18z-3+12z=10$$
$$63z-36-3+12z=10$$
$$63z-39+12z=10$$
$$75z-39=10$$
$$75z=10+39$$
$$75z=49$$
$$z=\frac{49}{75}$$
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