Solve |9| + |- 3| | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$|9|+|-3|$$

Evaluate

$12$

Solution Steps

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $9$ is $9$.

$$9+|-3|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-3$ is $3$.

$$9+3$$

Add $9$ and $3$ to get $12$.

$$12$$

Factor

$2^{2}\times 3$