How to solve 9+2 imes8-2-3=18

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9+2\times8-2-3=18 | Equatix

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a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

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$$9+2 \times 8-2-3=18$$

Verify

$\text{false}$

Solution Steps

Multiply $2$ and $8$ to get $16$.

$$9+16-2-3=18$$

Add $9$ and $16$ to get $25$.

$$25-2-3=18$$

Subtract $2$ from $25$ to get $23$.

$$23-3=18$$

Subtract $3$ from $23$ to get $20$.

$$20=18$$

Compare $20$ and $18$.

$$\text{false}$$

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