How to solve 9+4f-7zf=6,z=5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9+4f-7zf=6,z=5 | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$9+4f-7zf=6,z=5$$

Solve for f, z

$z=5$
$f=\frac{3}{31}\approx 0.096774194$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$9+4f-7\times 5f=6$$

Multiply $-7$ and $5$ to get $-35$.

$$9+4f-35f=6$$

Combine $4f$ and $-35f$ to get $-31f$.

$$9-31f=6$$

Subtract $9$ from both sides.

$$-31f=6-9$$

Subtract $9$ from $6$ to get $-3$.

$$-31f=-3$$

Divide both sides by $-31$.

$$f=\frac{-3}{-31}$$

Fraction $\frac{-3}{-31}$ can be simplified to $\frac{3}{31}$ by removing the negative sign from both the numerator and the denominator.

$$f=\frac{3}{31}$$

The system is now solved.

$$f=\frac{3}{31}$$ $$z=5$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for f, z

Solution Steps