Question

$$[9+5\div10\div15\div20](20\div4\times\frac{5}{9}]+\frac{4}{3})\{49?]$$

Evaluate

$-\frac{27005}{81}\approx -333.395061728$

Show Solution

Factor

$-\frac{27005}{81} = -333\frac{32}{81} = -333.39506172839504$