How to solve 9+5+8+6+9x635

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9+5+8+6+9x635 | Equatix

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Question

$$9+5+8+6+9x635$$

Evaluate

$9x_{635}+28$

Solution Steps

Add $9$ and $5$ to get $14$.

$$14+8+6+9x_{635}$$

Add $14$ and $8$ to get $22$.

$$22+6+9x_{635}$$

Add $22$ and $6$ to get $28$.

$$28+9x_{635}$$

Show Solution

Differentiate w.r.t. x_635

$9$

Steps Using Derivative Rule for Sum

Add $9$ and $5$ to get $14$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{635}}(14+8+6+9x_{635})$$

Add $14$ and $8$ to get $22$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{635}}(22+6+9x_{635})$$

Add $22$ and $6$ to get $28$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{635}}(28+9x_{635})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$9x_{635}^{1-1}$$

Subtract $1$ from $1$.

$$9x_{635}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$9\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$9$$