How to solve 9+9 imes9=3/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9+9\times9=3/9 | Equatix

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a⋅(b-2)=3b

3(r+2s)=2t-4

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$$9+9 \times 9=3/9$$

Verify

$\text{false}$

Solution Steps

Multiply $9$ and $9$ to get $81$.

$$9+81=\frac{3}{9}$$

Add $9$ and $81$ to get $90$.

$$90=\frac{3}{9}$$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$90=\frac{1}{3}$$

Convert $90$ to fraction $\frac{270}{3}$.

$$\frac{270}{3}=\frac{1}{3}$$

Compare $\frac{270}{3}$ and $\frac{1}{3}$.

$$\text{false}$$

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