$$[[9+\frac{1}{600}]\frac{37}{9}x-5]$$
$\frac{199837x}{5400}-5$
$$\left(\frac{5400}{600}+\frac{1}{600}\right)\times \frac{37}{9}x-5$$
$$\frac{5400+1}{600}\times \frac{37}{9}x-5$$
$$\frac{5401}{600}\times \frac{37}{9}x-5$$
$$\frac{5401\times 37}{600\times 9}x-5$$
$$\frac{199837}{5400}x-5$$
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