How to solve 8 3. 9+ 5 10 1000

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8 3. 9+ 5 10 1000 | Equatix

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Question

$$9 + \frac { 8 } { 10 } + \frac { 5 } { 1000 }$$

Evaluate

$\frac{1961}{200}=9.805$

Solution Steps

Reduce the fraction $\frac{8}{10}$ to lowest terms by extracting and canceling out $2$.

$$9+\frac{4}{5}+\frac{5}{1000}$$

Convert $9$ to fraction $\frac{45}{5}$.

$$\frac{45}{5}+\frac{4}{5}+\frac{5}{1000}$$

Since $\frac{45}{5}$ and $\frac{4}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{45+4}{5}+\frac{5}{1000}$$

Add $45$ and $4$ to get $49$.

$$\frac{49}{5}+\frac{5}{1000}$$

Reduce the fraction $\frac{5}{1000}$ to lowest terms by extracting and canceling out $5$.

$$\frac{49}{5}+\frac{1}{200}$$

Least common multiple of $5$ and $200$ is $200$. Convert $\frac{49}{5}$ and $\frac{1}{200}$ to fractions with denominator $200$.

$$\frac{1960}{200}+\frac{1}{200}$$

Since $\frac{1960}{200}$ and $\frac{1}{200}$ have the same denominator, add them by adding their numerators.

$$\frac{1960+1}{200}$$

Add $1960$ and $1$ to get $1961$.

$$\frac{1961}{200}$$

Show Solution

Factor

$\frac{37 \cdot 53}{2 ^ {3} \cdot 5 ^ {2}} = 9\frac{161}{200} = 9.805$